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\newtheorem{acknowledgement}[theorem]{Acknowledgement}
\newtheorem{algorithm}[theorem]{Algorithm}
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\begin{document}
Al ordenar los n\'{u}meros $\dfrac{10}{101},\dfrac{9}{100}$ y $\dfrac{7}{98}$
de mayor a menor se obtiene:\medskip\newline \qquad a) $\dfrac{7}{98}%
<\dfrac{9}{100}<\dfrac{10}{101}\qquad\qquad$b) $\dfrac{10}{101}<\dfrac{7}%
{98}<\dfrac{9}{100}\bigskip$\newline \qquad c) $\dfrac{9}{100}<\dfrac{7}%
{98}<\dfrac{10}{101}\qquad\qquad$d) $\dfrac{10}{101}<\dfrac{9}{100}<\dfrac
{7}{98}$

Al ordenar los n\'{u}meros $\dfrac{23}{48},\dfrac{14}{39}$ y $\dfrac{5}{30}$
de mayor a menor se obtiene:\medskip\newline \qquad a) $\dfrac{5}{30}%
<\dfrac{14}{39}<\dfrac{23}{48}\qquad\qquad$b) $\dfrac{23}{48}<\dfrac{14}%
{39}<\dfrac{5}{30}\bigskip$\newline \qquad c) $\dfrac{14}{39}<\dfrac{5}%
{30}<\dfrac{23}{48}\qquad\qquad$d) $\dfrac{14}{39}<\dfrac{23}{48}<\dfrac
{5}{30}$

Al ordenar los n\'{u}meros $\dfrac{71}{89},\dfrac{70}{89}$ y $\dfrac{72}{90}$
de mayor a menor se obtiene:\medskip\newline \qquad a) $\dfrac{70}{89}%
<\dfrac{71}{89}<\dfrac{72}{90}\qquad\qquad$b) $\dfrac{72}{90}<\dfrac{70}%
{89}<\dfrac{71}{89}\bigskip$\newline \qquad c) $\dfrac{72}{90}<\dfrac{71}%
{89}<\dfrac{70}{89}\qquad\qquad$d) $\dfrac{70}{89}<\dfrac{72}{90}<\dfrac
{71}{89}$

Al ordenar los n\'{u}meros $\dfrac{41}{81},\dfrac{62}{85}$ y $\dfrac{53}{83}$
de mayor a menor se obtiene:\medskip\newline \qquad a) $\dfrac{41}{81}%
<\dfrac{53}{83}<\dfrac{62}{85}\qquad\qquad$b) $\dfrac{53}{83}<\dfrac{41}%
{81}<\dfrac{62}{85}\bigskip$\newline \qquad c) $\dfrac{62}{85}<\dfrac{41}%
{81}<\dfrac{53}{83}\qquad\qquad$d) $\dfrac{41}{81}<\dfrac{62}{85}<\dfrac
{53}{83}$

Al ordenar los n\'{u}meros $\dfrac{25}{36},\dfrac{24}{37}$ y $\dfrac{23}{38}$
de mayor a menor se obtiene:\medskip\newline \qquad a) $\dfrac{23}{38}%
<\dfrac{24}{37}<\dfrac{25}{36}\qquad\qquad$b) $\dfrac{24}{37}<\dfrac{23}%
{38}<\dfrac{25}{36}\bigskip$\newline \qquad c) $\dfrac{25}{36}<\dfrac{24}%
{37}<\dfrac{23}{38}\qquad\qquad$d) $\dfrac{23}{38}<\dfrac{25}{36}<\dfrac
{24}{37}$

Al ordenar los n\'{u}meros $\dfrac{14}{79},\dfrac{13}{79}$ y $\dfrac{15}{80}$
de mayor a menor se obtiene:\newline \qquad\medskip a) $\dfrac{13}{79}%
<\dfrac{14}{79}<\dfrac{15}{80}$\qquad b) $\dfrac{13}{79}<\dfrac{15}{80}%
<\dfrac{14}{79}$\newline \qquad c) $\dfrac{15}{80}<\dfrac{13}{79}<\dfrac
{14}{79}$\qquad d) $\dfrac{15}{80}<\dfrac{14}{79}<\dfrac{13}{79}$

Al ordenar los n\'{u}meros $\dfrac{12}{59},\dfrac{11}{59}$ y $\dfrac{13}{60}$
de mayor a menor se obtiene:\newline \qquad\medskip a) $\dfrac{11}{59}%
<\dfrac{12}{59}<\dfrac{13}{60}$\qquad b) $\dfrac{12}{59}<\dfrac{11}{59}%
<\dfrac{13}{60}$\newline \qquad c) $\dfrac{13}{60}<\dfrac{11}{59}<\dfrac
{12}{59}$\qquad d) $\dfrac{11}{59}<\dfrac{13}{60}<\dfrac{12}{59}$

Al ordenar los n\'{u}meros $\dfrac{23}{71},\dfrac{25}{72}$ y $\dfrac{24}{71}$
de mayor a menor se obtiene:\newline \qquad\medskip a) $\dfrac{23}{71}%
<\dfrac{24}{71}<\dfrac{25}{72}$\qquad b) $\dfrac{25}{72}<\dfrac{23}{71}%
<\dfrac{24}{71}$\newline \qquad c) $\dfrac{23}{71}<\dfrac{25}{72}<\dfrac
{24}{71}$\qquad d) $\dfrac{24}{71}<\dfrac{25}{72}<\dfrac{23}{71}$

Al ordenar los n\'{u}meros $\dfrac{9}{83},\dfrac{11}{84}$ y $\dfrac{10}{83}$
de mayor a menor se obtiene:\newline \qquad\medskip a) $\dfrac{9}{83}%
<\dfrac{10}{83}<\dfrac{11}{84}$\qquad b) $\dfrac{11}{84}<\dfrac{9}{83}%
<\dfrac{10}{83}$\newline \qquad c) $\dfrac{9}{83}<\dfrac{11}{84}<\dfrac
{10}{83}$\qquad d) $\dfrac{10}{83}<\dfrac{11}{84}<\dfrac{9}{83}$

Al ordenar los n\'{u}meros $\dfrac{55}{91},\dfrac{57}{92}$ y $\dfrac{56}{91}$
de mayor a menor se obtiene:\newline \qquad\medskip a) $\dfrac{55}{91}%
<\dfrac{56}{91}<\dfrac{57}{92}$\qquad b) $\dfrac{55}{91}<\dfrac{57}{92}%
<\dfrac{56}{91}$\newline \qquad c) $\dfrac{56}{91}<\dfrac{57}{92}<\dfrac
{55}{91}$\qquad d) $\dfrac{57}{92}<\dfrac{55}{91}<\dfrac{56}{91}$

Al ordenar los n\'{u}meros $\dfrac{43}{87},\dfrac{45}{88}$ y $\dfrac{44}{87}$
de mayor a menor se obtiene:\newline \qquad\medskip a) $\dfrac{43}{87}%
<\dfrac{44}{87}<\dfrac{45}{88}$\qquad b) $\dfrac{43}{87}<\dfrac{45}{88}%
<\dfrac{44}{87}$\newline \qquad c) $\dfrac{44}{87}<\dfrac{45}{88}<\dfrac
{43}{87}$\qquad d) $\dfrac{45}{88}<\dfrac{43}{87}<\dfrac{44}{87}$

Al ordenar los n\'{u}meros $\dfrac{23}{61},\dfrac{25}{62}$ y $\dfrac{24}{61}$
de mayor a menor se obtiene:\newline \qquad\medskip a) $\dfrac{23}{61}%
<\dfrac{24}{61}<\dfrac{25}{62}$\qquad b) $\dfrac{25}{62}<\dfrac{23}{61}%
<\dfrac{24}{61}$\newline \qquad c) $\dfrac{24}{61}<\dfrac{25}{62}<\dfrac
{23}{61}$\qquad d) $\dfrac{23}{61}<\dfrac{25}{62}<\dfrac{24}{61}$

Al ordenar los n\'{u}meros $\dfrac{16}{37},\dfrac{18}{38}$ y $\dfrac{17}{37}$
de mayor a menor se obtiene:\newline \qquad\medskip a) $\dfrac{16}{37}%
<\dfrac{17}{37}<\dfrac{18}{38}$\qquad b) $\dfrac{18}{38}<\dfrac{16}{37}%
<\dfrac{17}{37}$\newline \qquad c) $\dfrac{17}{37}<\dfrac{18}{38}<\dfrac
{16}{37}$\qquad d) $\dfrac{16}{37}<\dfrac{18}{38}<\dfrac{17}{37}$

Al ordenar los n\'{u}meros $\dfrac{11}{97},\dfrac{13}{98}$ y $\dfrac{12}{97}$
de mayor a menor se obtiene:\newline \qquad\medskip a) $\dfrac{11}{97}%
<\dfrac{12}{97}<\dfrac{13}{98}$\qquad b) $\dfrac{12}{97}<\dfrac{13}{98}%
<\dfrac{11}{97}$\newline \qquad c) $\dfrac{13}{98}<\dfrac{11}{97}<\dfrac
{12}{97}$\qquad d) $\dfrac{11}{97}<\dfrac{13}{98}<\dfrac{12}{97}$

Al ordenar los n\'{u}meros $\dfrac{6}{41},\dfrac{8}{42}$ y $\dfrac{7}{41}$ de
mayor a menor se obtiene:\newline \qquad\medskip a) $\dfrac{6}{41}<\dfrac
{7}{41}<\dfrac{8}{42}$\qquad b) $\dfrac{6}{41}<\dfrac{8}{42}<\dfrac{7}{41}%
$\newline \qquad c) $\dfrac{7}{41}<\dfrac{8}{42}<\dfrac{6}{41}$\qquad d)
$\dfrac{8}{42}<\dfrac{6}{41}<\dfrac{7}{41}$
\end{document}